49x^2-70x+9=0

Solution for 49x^2-70x+9=0 equation:

49x^2-70x+9=0

a = 49; b = -70; c = +9;
Δ = b2-4ac
Δ = -702-4·49·9
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-56}{2*49}=\frac{14}{98}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+56}{2*49}=\frac{126}{98}
=1+2/7
$